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A mixture is prepared by mixing 29.27 mL of the blue dye solution with 35.00 mL of the red dye solution and 14.73 mL of the yellow dye solution. What is the molar concentration of the blue dye in the mixture

Answer :

okpalawalter8

If a mixture is prepared by mixing 29.27 mL of the blue dye solution with 35.00 mL of the red dye solution and 14.73 mL of the yellow dye solution, the molar concentration of the blue dye in the mixture is

MB'=0.1189M

What is the molar concentration of the blue dye in the mixture?

Generally, the equation for the moles  is mathematically given as

Moles=Molarity *volume

Therefore

For Blue dye

MB=0.3523*25.27*1/1000ml

MB=8.90*10^{-3}

For red dye

MR=0.1017*35.27*1/1000ml

MR=3.55*10^{-3}

For yellow dye

MY=0.3523*14.73*1/1000ml

MY=2.27*10^{-3}

Where

Total volume is

T=25.27+35.ml+14.73

T=75ml

In conclusion, The molar conc of blue dye is

[tex]MB'=\frac{8.90*10^{-3}*1000}{75}[/tex]

MB'=0.1189M

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