Answer:
(c) [tex]\displaystyle 10\:cm.[/tex]
Step-by-step explanation:
Split each diagonal in half and use the Pythagorean Theorem:
[tex]\displaystyle a^2 + b^2 = c^2 \\ \\ 8^2 + 6^2 = c^2 \hookrightarrow 64 + 36 = c^2 \hookrightarrow \sqrt{100} = \sqrt{c^2} \\ \\ \boxed{10 = c}[/tex]
I am joyous to assist you at any time.
Diagonals of a rhombus are perpendicular to each other .
We need Side
Use Pythagorean theorem
[tex]\\ \rm\rightarrowtail H^2=P^2+B^2[/tex]
[tex]\\ \rm\rightarrowtail H^2=6^2+8^2[/tex]
[tex]\\ \rm\rightarrowtail H^2=10^2[/tex]
[tex]\\ \rm\rightarrowtail H=10cm[/tex]
