Answer :

  • H-I bond enthalpy=295KJ/mol

So

  • No of moles=0.5

Now total enthalpy:-

  • ∆H=Bond enthalpy×Moles
  • ∆H=0.5(295)
  • ∆H=147.5KJ

Given data:

  • H-I bond enthalpy = 295KJ/mol

  • No. of moles = 0.5

  • change in bond enthalpy (∆H) = ?

Solution:

The standard formula for calculating change in bond enthalpy (∆H) is given by,

[tex]\longrightarrow\rm{∆h = bond \: enthalpy \times moles}[/tex]

[tex]\longrightarrow\rm{∆h =0.5 \times 295}[/tex]

[tex]\longrightarrow\rm{∆h = 147.5 \: KJ}[/tex]

The value of ∆H is 147.5KJ

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