Answer :

fieryanswererft

y² = 16

options provided:

A. y³ = 64

B. y³ = 8

✔ C. y² = 16

D. y² = 8

solve:

  • a) y³ = 64   ⇒    y = ³√64    ⇒   y = 4

  • b) y³ = 8     ⇒     y = ³√8     ⇒   2

  • c) y² = 16    ⇒     y = ±√16    ⇒    y = ±4

  • d) y² = 8    ⇒    y = ±√8     ⇒    ±2√2
  • y²=16

Let's see how?

We know a polynomial having degree n has n zeros

Here

  • degree is 2
  • So 2 zeros

Hence answer will be

  • ±4

Option C

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