Answer :
Answer:
y=-4x-3
Step-by-step explanation:
Hi there!
We are given the following two points: (-2,5) and (-1,1)
We want to write the equation of the line that passes through these two lines in slope-intercept form
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
First, let's find the slope
The formula for the slope (m) calculated from 2 points is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points
We have everything we need to calculate the slope, but let's label the value of the points to avoid any confusion
[tex]x_1=-2\\y_1=5\\x_2=-1\\y_2=1[/tex]
Now substitute into the formula
m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
m=[tex]\frac{1-5}{-1--2}[/tex]
Simplify
m=[tex]\frac{1-5}{-1+2}[/tex]
Subtract
m=[tex]\frac{-4}{1}[/tex]
Divide
m=-4
Now substitute -4 as m into the equation:
y=-4x+b
Now we need to find b
As the equation passes through both (-2, 5) and (-1, 1), we can use either point to help solve for b.
Taking (-2,5) for example:
Substitute -2 as x and 5 as y:
5=-4(-2)+b
Multiply
5=8+b
Subtract 8 from both sides
-3=b
Substitute -3 as b.
y=-4x-3
Hope this helps!
See more on this topic here: https://brainly.com/question/27304092