Answer:
x = 39
Step-by-step explanation:
Secant and tangent line from a point outside the cirlcle,
(length of th tangent)² = length of the secant * external segment
26² = (13 + x) * 13
[tex]\sf (13 +x)*13 = 26 *26\\[/tex]
[tex]\sf 13 + x =\dfrac{26*26}{13}[/tex]
13 + x = 2* 26
13 + x = 52
x = 52 - 13
x = 39
