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Water is flowing through a pipe with a velocity of 5 m/s. The pipe has a diameter of 6 cm. The pipe then goes up 3 meters and narrows to a diameter of 4 cm. If the gauge pressure in the lower part of the pipe is 80 kPa, what is the gauge pressure in the higher and more narrow part of the pipe

Answer :

The gauge pressure in the higher part will be 136 kph. The pressure is found with the help of the Bernoulli equation.

What is gauge pressure?

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

From the continuity equation;

[tex]\rm A_1v_1=A_2v_2 \\\\ \rm \frac{\pi}{4}(6)^2 \times 5 = \frac{\pi}{4}(3)^2 v_2 \\\\ v_1 = 20 \ m/sec[/tex]

The gauges pressure in the higher part is found as;

From the Bernoullis equation;

[tex]\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{80 \times 10^3 }{\rho g} + \frac{(5)^2}{2g} +0= \frac{p_2}{\rho g} + \frac{(20)^2}{2g} +3 \\\\ \frac{80 \times 10^3 - P_2 }{1000 \times 9.81 } = \frac{20^2-5^2}{2 \times 9.81 } +3 \\\\ P_2 = 136 \ kpa[/tex]

Hence the gauge pressure in the higher part will be 136 kpa.

To learn more about the gauge pressure refer to the link;

https://brainly.com/question/14012416

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