Answer :
In the elastic collision, the velocity of approach and velocity of separation is the same. The velocity of the separation after the collision will be 45 m/s.
What is collision?
The abrupt, violent coming together in direct contact of two bodies is known as the collision. a falling object and a floor are examples of collisions.
When the distance between two ships decreases while the bearings remain constant, a collision occurs.
Objects have an elastic collision. Before the collision, they approach one another V1= V2=45 m/sec
The velocity of the approach is found as;
[tex]\rm = U_1-U_2 \\\\\ = 45-45 \\\\ = 0[/tex]
As we know,
[tex]\rm e = \frac{U_2-U_1}{V_2-V_1}[/tex]
The velocity of separation is found as;
[tex]\rm V_1-V_2[/tex]
and, e=1 for elastic collision.
[tex]\rm U_1-U_2=V_2-V_1[/tex]
[tex]\rm V_2-V_1 = 0 \\\ V_2 = V_1 = 45 \ m/sec[/tex]
In the elastic collision, the velocity of approach and velocity of separation is the same.
Hence the velocity of the separation after the collision will be 45 m/s.
To learn more about the collision refer to the link;
brainly.com/question/13138178
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