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Flying with the wind, a plane flew 1,200 mi in 4 h. Against the wind, the plane required 6 h to fly the same distance. Find the rate of the plane in calm air and the rate of the wind.

Answer :

Hrishii

Answer:

Rate of plane = 250 mph

Rate of wind = 50 mph

Step-by-step explanation:

  • Let the speed of the plane in calm air be x mph
  • & speed of the wind be y mph
  • Speed of plane with wind = (x + y) mph
  • Speed of plane against wind = (x - y) mph
  • Formula relating speed, time and distance is given as: speed*time = distance
  • According to the first condition: (x+y)*4 = 1200
  • -> x + y = 300 (1)
  • According to the second condition: (x-y)*6= 1200
  • -> x - y = 200 (2)
  • Adding equations (1) & (2), we find:
  • 2x = 500
  • -> x = 250 (Dividing 500 by 2)
  • -> y = 50 (Plugging x = 250 in eq 1)
  • Rate of plane = 250 mph
  • Rate of wind = 50 mph

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