Answer :
Answer:
158 mL
158 mL of 0.1 M of HCl is required to react completely with 1 g mixture of Na2CO3 and NaHCO3, containing equimolar amounts of both
Explanation:
hope helpez -,-~
btw masoom bachi copied me~
Answer:
158 mL
158 mL of 0.1 M of HCl is required to react completely with 1 g mixture of Na2CO3 and NaHCO3, containing equimolar amounts of both
Explanation:
hope helpez -,-~
btw masoom bachi copied me~