chase1posey410
Answered

suppose you throw a ball straight up from the ground with a velocity of 224 feet per second. as the ball moves up, gravity slows it. eventually, the ball begins to fall back to the ground. the height h of thr ball after t seconds in the air is given by the equation h=-16t^2 + 224t. use the given information to answer.

a. find the height of the ball after four seconds. (type a whole number)

b. how long will it take the ball to reach a height of 768 ft?

c. how long after you throw the ball will it return to the ground? (type w whole number)

Answer :

oladayoademosu

a. The height of the ball after four seconds is 640 ft

b. The time the ball reachs a height of 768 ft is 6 s or 8 s.

c. The time the ball reachs the ground after it is thrown is 14 seconds.

Since the height of the ball is a parabola, we need to know the equation parabola is

What is a parabola?

A parabola is an equation of the form x(t) = at² + bt + c

a. Height of the ball after four seconds

The height of the ball after four seconds is 640 ft

Since the height of the ball is represented by the equation h(t) = -16t² + 224t. The height of the ball after four seconds is when t = 4.

So, h(t) = -16t² + 224t.

h(4) = -16(4)² + 224(4)

h(4) = -16(16) + 224(4)

h(4) = -256 + 896

h(4) = 640 ft

The height of the ball after four seconds is 640 ft

b. How long will it take the ball to reach a height of 768 ft?

The time it takes the ball to reach a height of 768 ft is 6 s or 8 s.

To find this time, we substituie h = 768 into the equation for the height of the ball.

So, h(t) = -16t² + 224t

768 = -16t² + 224t.

16t² - 224t + 768 = 0

t² - 14t + 48 = 0

Using the quadratic formula, we find t

[tex]t = \frac{-(-14) +/- \sqrt{(-14)^{2} - 4 X 1 X 48} }{2 X 1} \\t = \frac{14 +/- \sqrt{196 - 192} }{2}\\t = \frac{14 +/- \sqrt{4} }{2}\\t = \frac{14 +/- 2 }{2}\\t = \frac{14 + 2 }{2} or t = \frac{14 - 2 }{2}\\t = \frac{16}{2} or t = \frac{12}{2}\\t = 8 or 6[/tex]

So, the time it takes the ball to reach a height of 768 ft is 6 s or 8 s.

c. How long after you throw the ball will it return to the ground?

The time it takes the ball to reach the ground after it is thrown is 14 seconds.

To find the time it takes the ball to reach the ground, the height, h = 0.

So, h(t) = 0

-16t² + 224t = 0

-16t(t - 14) = 0

t(t - 14) = 0

t = 0 or t - 14 = 0

t = 0 or t = 14 s

So, the time it takes the ball to reach the ground after it is thrown is 14 seconds.

Learn more about equation of parabola here:

https://brainly.com/question/25651698

#SPJ1

Other Questions