Answer :
Using the Fundamental Counting Theorem, it is found that there are 60 ways for Alex to select three electives from them this semester.
What is the Fundamental Counting Theorem?
It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:
[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]
In this problem, we have that:
- The first choice is one of three of social studies, hence [tex]n_1 = 3[/tex].
- The second choice is one of four from science, hence [tex]n_2 = 4[/tex].
- The third choice is any of the remaining 5, hence [tex]n_3 = 5[/tex].
Then the number of ways is given by:
N = 3 x 4 x 5 = 60.
More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866
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Answer:
30 ways
Step-by-step explanation:
Using the Fundamental Counting Thereom we donate that n1 = 2 and not 3 as it is guaranteed to take 1 elective from Social Studies, and n2 = 3 and not 4 as it is also guaranteed to take 1 elective from Science. Then with 2 electives already gone, we only have 5 left making n3 = 5. Multiply these, we get 2*3*5 which is 30, meaning Alex can select three electives 30 ways with at least one from each subject.