Answer :
The volume of aluminum hydroxide required for neutralization is 24.30 mL.
Acid and base:
The compounds which gives H+ ions in the aqueous solution are called acids while those which gives OH- ions are called base.
Neutralization reaction:
It is a chemical reaction that involves a reaction between the equal molar amount of acid and base and form a solution that has pH = 7.
Calculations:
The reaction between aluminum hydroxide and nitric acid is expressed as:
Al(OH)2 + 2HNO3 ----> Al(NO3)2 + 2H2O
The number of moles of nitric acid is calculated as:
Moles of HNO3 = 0.175 M x (30.00/1000) L = 0.00525 mol
The number of moles of Al(OH)2 required for the neutralization is:
Moles of Al(OH)2 = 0.00525 mol/2 = 0.002625 mol
The volume of Al(OH)2 is calculated as:
Volume = 0.002625 mol/0.108 M = 0.0243 L = 24.30 mL
Learn more about neutralization reaction here:
https://brainly.com/question/20038776
#SPJ4