Answer :

The centripetal acceleration of the satellite will be less than acceleration due to gravity on earth (g).

Calculation of centripetal acceleration of satellite:

Let the radius of earth be, R

Let the radius of satellite be, R'

Let the gravitational constant be, G

Let the acceleration due to gravity (earth) be, g

Let the mass of earth be M

Step 1:

We know that the orbital velocity of satellite can be given as:

v =√GM/R'     - ( 1 )

Thus, the centripetal acceleration of the satellite will be:

a_c = v²/R' = GM/R'²            - ( 2 )

The acceleration due to gravity is given as:

g = GM/R²                             - ( 3 )

Step 2:

From equation 2 and 3 we get:

a_c/g = GM/R'² ÷ GM/R²

a_c/g = R²/R'²  < 1  

Step 3:

Thus we get:    

a_c/g < 1

a_c < g

Therefore, the centripetal acceleration of the satellite is smaller than acceleration due to gravity on earth.

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