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For the decomposition of nitrosyl bromide at 10 °C
2 NOBr(g)2 NO(g) + Br2(g)
the average rate of disappearance of NOBr over the time period from t = 0 s to t = 25.7 s is found to be 7.36×10-4 M s-1.

What is the average rate of appearance of Br2 over the same time period?

M s-1.

Answer :

pstnonsonjoku

From the calculation, the rate of appearance of Br2 is 1.472 * 10^-3 M s-1

What is the rate of reaction?

The rate of reaction refers to how fast or slow that reactants disappear or the products are  formed .

Now;

We know that;

-d[NOBr]/dt = 1/2 d[Br2]/dt

Hence;

d[Br2]/dt = 2[-d[NOBr]/dt ]

d[Br2]/dt = 2 (7.36×10-4 M s-1)

d[Br2]/dt =  1.472 * 10^-3 M s-1

Learn more about rate of reaction:https://brainly.com/question/8592296

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