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A firework is launched from the ground at a speed of 160 feet per second. It’s height after t seconds is given by the polynomial -16t+160t. What is the height of the firework after 4 seconds?

Answer :

Heather

Answer: 384 feet

Step-by-step explanation:

     We will simplify and solve -16t² + 160t when t is equal to 4.

-16t² + 160t

-16(4)² + 160(4)

384 feet

Dinofish32

Answer:

Step-by-step explanation:

**Note: The polynomial in question is -16t² + 160t, as clarified in the discussion under the question.**

Since there is a polynomial to find the height given a certain time, the height is a function of time.

This function would be h(t) = -16t² + 160t, so plugging in 4 for t would give the height.

[tex]h(4) = -16(4)^2+160(4)[/tex]

[tex]-16(16)+160(4)[/tex] [Squaring 4]

[tex]-256 + 640[/tex] [Multiplying]

[tex]384[/tex] [Combining both terms]

Hence, the height of the firework after 4 seconds is 384 feet.

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