The average rate of change of the function f(x) = x2 + 1 between x = -10 and x = 10 is 0
How to determine the average rate of change of the function f(x) = x2 + 1 between x = -10 and x = 10?
The function is given as
f(x) = x^2 + 1
The interval is given as:
x = -10 and x = 10
Calculate f(-10) and f(10)
f(-10) = (-10)^2 + 1 = 101
f(10) = (10)^2 + 1 = 101
The average rate of change of the function f(x) = x2 + 1 between x = -10 and x = 10 is then calculated as:
m = f(10) - f(-10)]/(10 - (-10)]
This gives
m = (101 - 101)/(10 + 10)
Evaluate
m = 0
Hence, the average rate of change of the function f(x) = x2 + 1 between x = -10 and x = 10 is 0
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