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(a) Ozone formation in the upper atmosphere starts when oxygen molecules absorb UV radiation of wavelengths ≤ 242 nm. Find the frequency and energy of the least energetic of these photons.

Answer :

Frequency and energy of least energetic photons is [tex]1.24*10^{15}[/tex] Hz and  [tex]8.2*10^{-19}[/tex] J respectively.

As frequency is inversely proportional to wavelength, the  least energetic photon will have highest wavelength. So, the given wavelength is highest, which is ≤ 242 nm.

Now, we know, 1 nm = [tex]10^{-9}[/tex] m

λ [tex]= 2.42*10^{-7}[/tex] m

Now, using the relation -

c = fλ, where c is speed of light, f is frequency and λ is wavelength

Also, c = [tex]3*10^{8}[/tex] m/s

f = c/λ

f = [tex]\frac{3*10^{8}} {2.42*10^{-7}}[/tex]

f = [tex]1.24*10^{15}[/tex] Hz

Now, calculating energy by the formula -

E = hf, where E is energy, h is planck's constant and f is frequency.

As, we know, h = [tex]6.63*10^{-34}[/tex] Js

E =  [tex]6.63*10^{-34}[/tex]* [tex]6.63*10^{-34}[/tex]

E = [tex]8.2*10^{-19}[/tex] J

Hence, the frequency and energy of the least energetic of these photons is  [tex]1.24*10^{15}[/tex] Hz and  [tex]8.2*10^{-19}[/tex] J respectively.

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