in a buffer containing acetic acid (ch2cooh) and sodium acetate (nach2coo-) at a ph of 5, if the concentration of sodium acetate is 100. mm, what is the concentration of acetic acid?

Answer :

By using the Henderson-Hasselbalch equation, we can calculate that the concentration of acetic acid in the given buffer is 57.5 mM.

When calculating the pH value of a buffer system, we use the Henderson-Hasselbalch equation:

[tex]pH = pK_{a} + log\frac{[base]}{[acid]}[/tex]

pKa - the negative logarithm of the acidic constant (for acetic acid, pKa = 4.76)

[base] - concentration of the basic (sodium acetate) component

[acid] - concentration of the acidic (acetic acid, AcOH) component

If we plug the known values (pH = 5; [base] = 100 mM; pKa = 4.76) in the equation we get:

[tex]5 = 4.76 + log\frac{100 mM}{[AcOH]}[/tex]

[tex]log\frac{100 mM}{[AcOH]} = 5-4.76[/tex]

[tex]log\frac{100 mM}{[AcOH]} = 0.24[/tex]

[tex]\frac{100 mM}{[AcOH]}= 10^{0.24}[/tex]

[tex]\frac{100 mM}{[AcOH]}= 1.74[/tex]

[AcOH] = 100 mM / 1.74

[AcOH] = 57.5 mM

You can learn more about buffers here:

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