Answer :
The empirical formula of the compound is C₂H₂S if the carbon content in the carbon dioxide obtained is 41.34% and the hydrogen content in the water obtained is 3.47%.
If the percentage of carbon content is 41.34% and hydrogen content is 3.47%, we can determine the percentage of sulfur content as follows;
percentage of sulfur = 100% - 41.34% - 3.47% = 55.19%
Now considering 100g of the compound;
Carbon = (41.34/100) × 100 = 41.34 g
Hydrogen = (3.47/100) × 100 = 3.47 g
Sulfur = (55.19/100) × 100 = 55.19 g
Now we can determine the moles of carbon, hydrogen, and sulfur by using their molar mass as follows;
Carbon: 41.34 ÷ 12.011 = 3.44 moles (Moles = mass ÷ molar mass)
Hydrogen: 3.47 ÷ 1.00784 = 3.44 moles
Sulfur: 55.19 ÷ 32.065 = 1.72 moles
Now by dividing each of the mole values by the smallest determined number of moles (1.72 moles), we can calculate the empirical formula as follows;
Carbon = 3.44 / 1.72 = 2
Hydrogen = 3.44 / 1.72 = 2
Sulfur = 1.72 / 1.72 = 1
Therefore the empirical formula of the compound will be C₂H₂S
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