For them, let x = number of children of the party and
A=Adventure Plext cost
B= Bright Child cost
C= Chuck E Cheese cost
So,
[tex]\begin{gathered} A=300+12x \\ B=180+15x \\ C=18x \end{gathered}[/tex]
Then, graphing each equation of the system of equations
Now, for determine the break even point for Chuck E Cheese and Bright Child you have
[tex]\begin{gathered} 180+15x=18x \\ 180=18x-15x \\ 180=3x \\ \frac{180}{3}=x \\ 60=x \end{gathered}[/tex]
That is, the break even point for Chuck E Cheese and Bright Child occurs when x = 60 children.
For determine the break even point for Adventure Plex and Bright Child you have
[tex]\begin{gathered} 300+12x=180+15x \\ 300+12x-180=180+15x-180 \\ 120+12x=15x \\ 120+12x-12x=15x-12x \\ 120=3x \\ \frac{120}{3}=\frac{3x}{3} \\ 40=x \end{gathered}[/tex]
That is, the break even point for Adventure Plex and Bright Child occurs when x = 40 children.
Finally, For determine the break even point for Adventure Plex y Chuck E Cheese you have
[tex]\begin{gathered} 300+12x=18x \\ 300+12x-12x=18x-12x \\ 300=6x \\ \frac{300}{6}=\frac{6x}{6} \\ 50=x \end{gathered}[/tex]
That is, the break even point for Adventure Plex and Chuck E Cheese occurs when x = 50 children.