The volume of a cone is given by the formula:
[tex]\begin{gathered} V=\frac{1}{3}\times\pi\times r^2\times h \\ r\text{ is the radius} \\ h\text{ is the height} \end{gathered}[/tex]From the question, we are provided with following:
[tex]\begin{gathered} h=27m \\ \theta=45^0 \end{gathered}[/tex]We have to use the given parameters to obtain the radius of the cone.
Thus, we have:
[tex]\begin{gathered} \text{Tan 45}^0=\frac{opposite}{\text{adjacent}} \\ 1=\frac{27}{\text{radius}} \\ \text{Therefore, radius=27m} \end{gathered}[/tex]Therefore, the volume of the cone is:
[tex]\begin{gathered} V=\frac{1}{3}\times\frac{22}{7}\times27^2\times27 \\ V=20,611.98m^3 \end{gathered}[/tex]Hence, the correct option is option BH