Given the focus and directrix shown on the graph, what is the vertex form of the equation of the parabola?

[tex]x\ =\ \frac{1}{10}(y\ -\ 3)^2\ -\ \frac{3}{2}[/tex]

[tex]x\ =\ 10(y\ +\ 3)^2\ +\ \frac{3}{2}[/tex]

[tex]x\ =\ \textrm{-}\frac{1}{10}(y\ -\ 3)^2\ -\ \frac{3}{2}[/tex]

[tex]y\ =\ \frac{1}{10}(x\ -\ 3)^2\ -\ \frac{3}{2}[/tex]