Answer :
Given a quadratic equation in standard form
[tex]y=ax^2+bx+c[/tex]The discriminant D
[tex]D=b^2-4ac[/tex]tells the types of roots the equation has.
In this case, we have
[tex]\begin{gathered} -2x^2+3x+5=0 \\ a=-2 \\ b=3 \\ c=5 \end{gathered}[/tex]Then, the discriminant of this quadratic equation will be
[tex]\begin{gathered} D=b^2-4ac \\ D=(3)^2-4(-2)(5) \\ D=9+40 \\ \mathbf{D=49} \end{gathered}[/tex]Finally, the value of discriminat is 49 and as he discriminant is greater than zero then this quadratic equation has 2 different real solutions.