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One card is selected from a deck of playing cards. What is the probability that the card selected is either a club or a face card?

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Solution

For this case we can define the following events:

C= the card selected is a club

F= the card selected is a face card

We want to find this probability:

[tex]P(\text{CUF)}[/tex]

We can use the total rule of probability and we have:

[tex]P(\text{CUF)}=P8C)+P(F)-P(C\cap F)[/tex]

And we can find the individual probabilities like this:

[tex]P(C)=\frac{13}{52}[/tex][tex]P(F)=\frac{12}{52}[/tex]

And the intersection is given by:

[tex]P(C\cap F)=\frac{3}{52}[/tex]

Replacing we have:

[tex]P(\text{CUF)}=\frac{13}{52}+\frac{12}{52}-\frac{3}{52}=\frac{22}{52}=\frac{11}{26}[/tex]

Then the answer is:

11/26

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