One number is equal to the square of another. Find the numbers if both are positive and their sum is 2450.

Explanation
Step 1
set the equations
a)
let x represents the first number
let y represents the second number
so
b) translate:
One number is equal to the square of another, hence
[tex]x=y^2\Rightarrow equation(1)[/tex]both are positive and their sum is 2450
[tex]x+y=2450\Rightarrow equation(2)[/tex]Step 2
solve the equations,
a) replace the x value from equation (1) into equation (2)
[tex]\begin{gathered} x+y=2450\Rightarrow equation(2) \\ replace \\ y^2+y=2450 \\ subtract\text{ 2450 in both sides } \\ y^2+y-2450=2450-2450 \\ y^2+y-2450=0\Rightarrow equation(3) \end{gathered}[/tex]b) now, need to solve the quadratic equation, to do that, we can use the quadratic formula
rememeber:
[tex]\begin{gathered} for \\ ax^2+bx+c=0 \\ t\text{he solution for x is } \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]hence