Answer :
Given:
V1= 88 ml
P1= 1 atm
T1= 25°C= 298.15 K
STP conditions:
P2= 1atm
T2= 273.15 K
Apply :
[tex]\frac{P1V1}{T1}=\frac{P2V2}{T2}[/tex]Replacing:
[tex]\frac{1(88)}{298.15}=\frac{1(V2)}{273.15}[/tex][tex]88(273.15)=298.15V2[/tex][tex]\frac{88(273.15)}{298.15}=V2[/tex]V2= 80.62 ml