Answer :
Since the formula:
[tex]A=45e-0.0045t[/tex]Corresponds to a linear funtion, t as the variable.
The inicial amount of this substance is the independent value (suposse t=0), in this case 45e.
Since the formula:
[tex]A=45e-0.0045t[/tex]Corresponds to a linear funtion, t as the variable.
The inicial amount of this substance is the independent value (suposse t=0), in this case 45e.