A soft drink machine is regulated so that it discharges an average of 8 ounces per cup. If the amountof drink per cup is normally distributed with a standard deviation of 0.5 ounce, find the probability acup contains less than 8.8 ounces.

Answer :

[tex]\begin{gathered} \mu=8 \\ \sigma=0.5 \end{gathered}[/tex][tex]\begin{gathered} P(Z<\frac{X-\mu}{\sigma}) \\ P(Z<\frac{8.8-8}{0.5}) \\ P(Z<1.6) \end{gathered}[/tex]

Using the z-table:

[tex]P(X<8.8)\approx0.9452[/tex]

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