DC=3
Perimeter=12
Explanation
Step 1
in a squre ,opposite sides are congruent , then
side A= sideB
then
we have a rigth triangle , then
[tex]\begin{gathered} \text{side}^2+side^2_2=hypotenuse^2 \\ as\text{ the sides are equal} \\ 2\cdot side^2=(3\sqrt[]{2})^2 \\ 2\cdot\text{side}^2=9\cdot2 \\ \text{side}^2=\frac{18}{2} \\ \text{side}=\sqrt[]{9} \\ \text{side}=3 \end{gathered}[/tex]
in a square ,all sides are congruent, then
[tex]\begin{gathered} \text{side}1=\text{side}2=\text{side}3=\text{side}4 \\ \text{Perimeter}=\text{ 4}\cdot side \\ \text{Perimeter}=4\cdot3 \\ \text{Perimeter}=12 \end{gathered}[/tex]
I hope this helps you
