I need help with find the length of side AC[tex]can \: u \: help \: me \: on \: us[/tex]
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When two triangles are similar, the ratio of their corresponding sides are equal
Thus, we have it that;
[tex]\begin{gathered} \frac{AB}{AC}\text{ = }\frac{PQ}{PR} \\ \frac{20}{AC}\text{ = }\frac{50}{40} \\ \\ AC\text{ = }\frac{40\times20}{50}\text{ = 16} \end{gathered}[/tex]