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how do I do this???
Consider the chemical reaction 2NH3(g) N2(g) + 3H2(g). The equilibrium is to be established in a 1.0-L container at 1000 K, where Kc = 4.0 × 10–2. Initially, 1.22 moles of NH3(g) are present. What is the equilibrium concentration of H2(g)?

Answer :

MissPhiladelphia
The chemical reaction is as follows:

2NH3(g) = N2(g) + 3H2(g)

We do the ice method to answer this. 
                
            NH3            N2             H2
I          1.22              0                0
C          -2x              x                3x 
E        1.22 - 2x       x                3x

Kc = [h2]^3 [n2] / [nh3]^2
4.0 × 10^–2 = 27x^3(x) /  (1.22 - 2x )^2
x = 0.259 mol

H2 = 0.259/1 = 0.259 mol/L

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