Answer :
A race car traveling at 44 meters per second on a racetrack and reducing its speed steadily over the course of 11 seconds to 22 meters per second would have covered 363 meters.
Which three motion equations are there?
Newton provided three equations of motion.
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
Remember that these equations only allow for uniform acceleration.
as stated in the issue We must determine the distance traveled by a race car if it moves along a racetrack at 44 meters per second and gradually slows down to 22 meters per second over the course of 11 seconds.
Using the initial motion equation,
v = u + at
22 = 44 + 11a
a = 22-44/11
a = -2 m/s²
The third equation of motion is used in the,
v² - u² = 2×a×s
22² - 44² = 2×(-2)s
s = 363 meters
The race car would have covered 363 meters.
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