Using the distance of the 1998KY 26 ​ in the small angle equation, we find: angular speed in "/sec/206265 ′′ = linear speed in meters/sec/4.35×10 9 m ​ Compute the linear speed of 1998KY 26 ​ in meters per second and note the answer below. Show your work

5. What is the value below closest to the speed of the 1998KY 26 ​ you computed above?

a) 100 meters/second d) 5000 meters/second b) 1100 meters/second e) 10000 meters/second c) 2000 meters/second