Answer :

[tex]\bf \begin{cases} c(x)=4x-2\\\\ d(x)=x^2+5x \end{cases}\qquad thus \\\\\\ (c\circ d)(x)\implies \begin{array}{llll} c(x)=&4x-2\\\\ c[\ d(x)\ ]=&4(dx)-2\\\\ c[\ \boxed{x^2+5x}\ ]= &4(\boxed{x^2+5x})-2 \end{array} [/tex]

distribute and simplify

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