Answer :
it's 61.5m
by solving simultaneously equations
29+d = 6t (bear)
d=4.1t (tourist)
by solving simultaneously equations
29+d = 6t (bear)
d=4.1t (tourist)
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.1 m/s. The car is a distance d away. The bear is 29 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?
61.5m
61.5m