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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.1 m/s. The car is a distance d away. The bear is 29 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

Answer :

mathssydney
it's 61.5m

by solving simultaneously equations  
29+d = 6t   (bear)
d=4.1t          (tourist)


Jayland
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.1 m/s. The car is a distance d away. The bear is 29 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

61.5m

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