Answer :

distance between (8,-3) and (4,-7), im pretty sure is 4
texaschic101
d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(8,-3)....x1 = 8 and y1 = -3
(4,-7)....x2 = 4 and y2 = -7
now we sub
d = sqrt (4 - 8)^2 + (-7 - (-3)^2
d = sqrt (-4^2 + (-4^2)
d = sqrt (16 + 16)
d = sqrt 32

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