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A tennis ball is served 2.5m above the ground at an angle of 5° above the horizontal direction with an initial speed of 30m/s. (a) When will it hit the ground? (b) How far will it travel

Answer :

jprazanth
a). time taken =(2 * V * sin theta)/ g = 3.061 seconds.

b). Range = (v^2 * sin 2 theta)/g = 10.53 meters

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