Answer :

irspow
The first term, a is √3 and the common ratio r is 2 and the general form of a geometric sequence is:

a(n)=a*r^(n-1)  so:

a(n)=√3*2^(n-1)

Answer:

[tex]a_n = \sqrt{3} \cdot (2)^{n-1}[/tex]

Step-by-step explanation:

The nth term for the geometric sequence is given by:

[tex]a_n = a_1 \cdot r^{n-1}[/tex]            ....[1]

where

[tex]a_1[/tex] is the first term

r is the common ratio term.

As per the statement:

A  sequence when [tex]a_1[/tex]= √3 and r = 2

then substitute these in [1] we have;

[tex]a_n = \sqrt{3} \cdot (2)^{n-1}[/tex]

Therefore,  a general rule for the nth term of the sequence is, [tex]a_n = \sqrt{3} \cdot (2)^{n-1}[/tex]

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