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Simplify 3 square root of 5 end root minus 2 square root of 7 end root plus square root of 45 end root minus square root of 28.

Answer :

nachoyoda
Simplify √ 45 to 3√ 5 and √ 28 to 2√ 7
Which gives you (3√5 +3√ 5 )+(−2√ 7 −2√ 7 )
Combine like terms = 6√ 5 −4√ 7
Done​​
SociometricStar

Answer:

The simplified expression is [tex]6\sqrt5-4\sqrt7[/tex]

Step-by-step explanation:

We have been given the expression

[tex]3\sqrt5-2\sqrt7+\sqrt{45}-\sqrt{28}[/tex]

Let us rewrite the numbers inside the square root as a product of two numbers in which at least one of them is a perfect square.

[tex]3\sqrt5-2\sqrt7+\sqrt{9\times5}-\sqrt{4\times7}[/tex]

Now, we know that

[tex]\sqrt9 = 3\text{ and }\sqrt4=2[/tex]

Thus, we have

[tex]3\sqrt5-2\sqrt7+3\sqrt{5}-2\sqrt{7}\\\text{Combining the like terms, we get}\\6\sqrt5-4\sqrt7[/tex]

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