Answer :
Each mol Ba(OH)2 releases 2 mol OH-
Ba(OH)2 -----> Ba2+ + 2OH-
[Ba2+] = 0.500 M
[OH-] = 1.00 M
This assumes complete ionization (dissociation) of Ba(OH)2.
Ba(OH)2 -----> Ba2+ + 2OH-
[Ba2+] = 0.500 M
[OH-] = 1.00 M
This assumes complete ionization (dissociation) of Ba(OH)2.