Answered

A pilot and a flight attendant get married and leave for their honeymoon on an airplane. Well-meaning friends pack the plane with balloons. As the plane gains altitude, the balloons begin to pop. -Using the ideal gas law, explain why the balloons popped. -One balloon was only partly filled when put on the plane. During the flight, the balloon volume increased from 7 L at 1.0 atm to 9 L. What was the cabin pressure on the airplane during the flight? (Assume the balloon stretched very easily and the temperature was

Answer :

The balloons popped because

  • As plane rise, the pressure in the cabin is decreases at constant temperature. According to Boyle's law the pressure is inversely proportional to the volume. Therefore, as pressure decreases then volume increases and cause balloon  to pop.
  • The pressure of the cabin  is 0.77 atm.

What is expression of Boyle's law?

The expression of  Boyle's law is given as,

P ∝ 1/V

P = K/V

  • K is proportionality constant
  • P is pressure of the gas
  • V is volume of the gas

Calculation,

Let P1 = Initial pressure = 1 atm

P2 = Final pressure = ?

V1 = Initial volume - 7 L

V2 = Final volume = 9 L

Then two Boyle's law expression are,

P1 = K/V1

K = P1V1             ...(i)

And, P2 = K/V2

K = P2V2         ...(ii)

Comparing equation i and ii we get,

P1V1 = P2V2

Putting the values of P1, V1 and V2 from question in above equation then we get the value of P2,

7 L×1 atm = P2×9 L

P2 = 0.77 atm

So, the cabin's pressure is 0.77 atm.

learn about Boyle's law,

https://brainly.com/question/13821925

#SPJ2

Other Questions