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Airplane a is flying directly toward the airport which is 20 miles away. The pilot notices airplane b 45 degrees to her right. Airplane b is also flying directly to the airport. The pilot of airplane b calculates that airplane a is 50 degrees to his left. Based on that information, how far is airplane b from the airport

Answer :

mathnstuff
First, set up your equation:
[tex] \frac{sin50}{20} = \frac{sin45}{x} [/tex]

Next, you cross multiply:
10[tex] \sqrt{2} [/tex] = sin50 x

Finally, isolate the variable to get your answer:
18.46 miles

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