Answer :
log(ab)=log(a)+log(b)
log_a(a)=1
so
[tex]log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=[/tex][tex]1+log_3(x+1)+log_3(x+2)[/tex]
log_a(a)=1
so
[tex]log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=[/tex][tex]1+log_3(x+1)+log_3(x+2)[/tex]