James20031
Answered

Dwayne Wade made 439 field goals out of 937 attempts. What was Dwayne Wade's ratio of successful field goals to attempt?

Answer :

kemanci
Let's set this ratio up as a fraction: (successful field goals)/(field goal attempts)
There were 439 successful field goals and 937 attempts: 439/937
The fraction cannot be reduced, so the ratio is 439/937.
aachen

Answer:

[tex]\frac{439}{937}[/tex]

Step-by-step explanation:

Given: Dwayne Wade made 439 field goals out of 937 attempts

To Find: Dwayne Wade's ratio of successful field goals to attempt

Solution:

Total field goals made by Dwayne Wade= [tex]439[/tex]

Total attempt Dwayne Wade made = [tex]937[/tex]

Now,

ratio of successful field goals to attempt made = [tex]\frac{\text{Total successful goals fielded by Dwayne Wade}}{\text{Total attempts}}[/tex]

on putting values,

ratio of successful field goals to attempt made = [tex]\frac{439}{937}[/tex]

As the fraction can not be simplified more,

Dwayne Wade's ratio of successful field goals to attempt is  [tex]\frac{439}{937}[/tex]

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