thezombieunicorn
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Suppose you have a bag of red, blue, and yellow marbles. If the probability of picking a red marble is1/6 and the probability of picking a yellow marble is 1/2, what is the probability of picking a blue marble?
1. 1/4
2.1/3
3.2/3
4.1/8

Answer :

irspow
The probabilities of picking a red, blue, and yellow marble must be equal to 1. so

P(R)+P(Y)+P(B)=1

1/6+1/2+P(B)=1  making all terms have a common denominator of 6 we have:

1+3+6P(B)=6

4+6P(B)=6

6P(B)=2

P(B)=2/6

P(B)=1/3

The probability of picking a blue marble is 1/3.

What is probability?

"Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one".

For the given situation,

The probability of picking red marbles = 1/6

The probability of picking yellow marbles = 1/2

The probability of picking blue marbles be 'x'

The total probability is expressed from zero to one, P(e) = 1.

[tex]P(e) = \frac{1}{6}+\frac{1}{2}+x\\[/tex]

⇒[tex]1=\frac{4}{6} +x[/tex]

⇒[tex]x=1-\frac{4}{6}[/tex]

⇒[tex]x=\frac{2}{6}[/tex]

⇒[tex]x=\frac{1}{3}[/tex]

Hence we can conclude that the probability of picking a blue marble is 1/3.

Learn more about probability here

brainly.com/question/13604758

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