Answer :
We can use the formula for area of a triangle to solve this problem A = (1/2)ab where a is the altitude or height and b is the base also we know that a = 4b in this problem and we know that A = 18 sq ft so 18 = (1/2)(4b)b 18 = 2b2 9 = b2 b = 3 so the base is 3 and the height is 4 times that a = 4(3) = 12 (height of the sail Hope this helps
Let the width (base) be w. Then the height is 4w. The area of this right triangle is then (base)(height)/2, which must equal 18 square meters.
Substituting the base and height:
(w)(4w)=18 square meters
Thus, 4w^2=18 square meters. Solving for w, w^2=18/4, or w=+9 meters. The height is 4 times that: h = 4(9 meters) = 36 meters.
Substituting the base and height:
(w)(4w)=18 square meters
Thus, 4w^2=18 square meters. Solving for w, w^2=18/4, or w=+9 meters. The height is 4 times that: h = 4(9 meters) = 36 meters.