Answer :
[tex]\dfrac{\mathrm d^2y}{\mathrm dx^2}+16\dfrac{\mathrm dy}{\mathrm dx}+73y=0\implies r^2+16r+73=0[/tex]
[tex]\implies r=-8\pm3i[/tex]
[tex]\implies\begin{cases}y_1=e^{-8x}\cos3x\\y_2=e^{-8x}\sin3x\end{cases}[/tex]
[tex]\implies r=-8\pm3i[/tex]
[tex]\implies\begin{cases}y_1=e^{-8x}\cos3x\\y_2=e^{-8x}\sin3x\end{cases}[/tex]