Answer :
Use the "distance formula" derived from the Pythagorean Theorem:
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(5-1)^2+(0--8)^2
d^2=16+64
d^2=80
d=√80
d≈8.9 units (to the nearest tenth of a unit)
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(5-1)^2+(0--8)^2
d^2=16+64
d^2=80
d=√80
d≈8.9 units (to the nearest tenth of a unit)