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Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = 3x^2 – 12x + 12

2 points in common; vertex above x-axis
2 points in common; vertex below x-axis
no points in common; vertex above x-axis
1 point in common; vertex on x-axis

Answer :

emarina
The answer is D, vertex on x - axis, also let me check that last question again

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